How do you factor by grouping #6x^3 - 2x + 3x^2 - 1#?

Question

2816 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-04-30T08:49:01

we are given, 6#x^3# #-# 2#x# #+ #3#x^2# #-# 1

on rearrangement:

#=# 6#x^3# #+# 3#x^2# #-# 2#x# #-# 1

The first two terms have 3#x^2# in common and the last two terms have #-#1 in common:

taking out the common terms:

#=# 3#x^2# ( #2x# + 1) #-# 1 ( 2#x# #+# 1)

making groups of two:
#=# (3 #x^2# #-#1) ( #2x# #+# 1 )