How do you factor by grouping $8st+28t-10s-35$ ?

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Answer 1 · 2015-04-10T10:08:18

We can factorize the expression by forming groups of 2 terms.

$8st+28t-10s-35$

$= (8st+28t)+(-10s-35)$

$4t$ is a common factor in the first group, and $-5$ is a common factor in the second.

$= 4t(2s+7) + (-5)*(2s+7)$

$color(green)( = (2s+7) * (4t - 5)$ is the factorised form of $8st+28t-10s-35$

How do you factor by grouping 8st+28t-10s-358st+28t-10s-35?