Question

How do you factor by grouping `m^3 + 3m^2n + 3mn^2 +n^3`?

Answer 1

`m^3+n^3 +3mn (m+n)`

= `(m+n)(m^2 -mn +n^2)+3mn(m+n)`

= `(m+n)(m^2-mn+n^2 +3mn)`

= `(m+n)(m^2+2mn+n^2)`

= `(m+n)(m+n)^2`

= `(m+n)^3`