# How do you factor by grouping m^4+m^3-12m-12?

May 2, 2015

You may notice that the first two have something in common, and so do the other two.

$= \left({m}^{4} + {m}^{3}\right) + \left(- 12 m - 12\right)$

So we take the common factors of both groups out of the brackets:

$= {m}^{3} \left(m + 1\right) - 12 \left(m + 1\right)$ watch the signs!

Now we recombine:

$= \left({m}^{3} - 12\right) \left(m + 1\right)$