How do you factor by grouping $y^{2} - 3 y - x y + 3 x$ $y^2-3y-xy+3x$ ?

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How do you factor by grouping $y^{2} - 3 y - x y + 3 x$ $y^2-3y-xy+3x$ ?

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Answer 1 · 2015-05-17T08:02:00

$y^{2} - 3 y - x y + 3 x$ $y^2 - 3y - xy +3x$

We factor this expression by making groups of 2 terms
$= (y^{2} - 3 y) + (- x y + 3 x)$ $= (y^2 - 3y) + (-xy +3x)$

Now we take the common factors out from each group
$= y (y - 3) - x (y - 3)$ $= y( y -3) -x(y-3)$

$(y - 3)$ $( y - 3)$ is a common factor to each of the terms now,
$= (y - 3) (y - x)$ $= (y-3)(y - x)$
$(y - 3) (y - x)$ $color(green)( (y-3)(y - x))$ is the Factorised form of $y^{2} - 3 y - x y + 3 x$ $y^2 - 3y - xy +3x$

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How do you factor by grouping $y^{2} - 3 y - x y + 3 x$ $y^2-3y-xy+3x$ ?

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How do you factor by grouping $y^{2} - 3 y - x y + 3 x$ $y^2-3y-xy+3x$ ?