# How do you factor completely 2b^2-2b-12?

$2 \left(b - 3\right) \left(b + 2\right)$
First factorise by dividing everything by $2$ and putting a $2$ outside the brackets.
$2 \left({b}^{2} - b - 6\right)$
$2 \left(b - 3\right) \left(b + 2\right)$