# How do you factor completely  2x^2 + 36x + 162?

Apr 25, 2016

See below..

#### Explanation:

$2 {x}^{2} + 36 x + 162$ (divide 2) gives you:
${x}^{2} + 18 x + 81$, then you have to factorise it.

When you factorise it, it should look like that: $\left(x + a\right) \left(x + b\right) = 0$

But before you factorise, you should first find out what factors (a and b) of 81 that add to 18. In that case, 9 and 9 are the factors that add to 18 and multiply to 81.

$\left(x + 9\right) \left(x + 9\right)$