# How do you factor completely 3x^3 + 24x^2 + 48x?

Jul 31, 2016

$= 3 x {\left(x + 4\right)}^{2}$

#### Explanation:

$3 {x}^{3} + 24 {x}^{2} + 48 x$
$= 3 x \left({x}^{2} + 8 x + 16\right)$
$= 3 x \left({x}^{2} + 2 x \left(4\right) + {4}^{2}\right)$
$= 3 x {\left(x + 4\right)}^{2}$

Jul 31, 2016

=$3 x \left(x + 4\right) \left(x + 4\right)$

#### Explanation:

Take out a common factor first. In this case $3 x$

$3 {x}^{3} + 24 {x}^{2} + 48 x$

=$3 x \left({x}^{2} + 8 x + 16\right)$

=$3 x \left(x + 4\right) \left(x + 4\right)$