# How do you factor completely  3x^3-36x^2+96x?

Aug 3, 2016

$3 x \left(x - 8\right) \left(x - 4\right)$.

#### Explanation:

Observe that $3 x$ is common in every term. We take it out, & get,

The Expression $= 3 x \left({x}^{2} - 12 x + 32\right)$

$= 3 x \left\{{x}^{2} - 8 x - 4 x + 32\right\} \ldots \ldots \ldots \ldots \ldots \left[8 \times 4 = 32 , 8 + 4 = 12\right]$

$= 3 x \left\{x \left(x - 8\right) - 4 \left(x - 8\right)\right\}$

$= 3 x \left(x - 8\right) \left(x - 4\right)$.