How do you factor completely #3x^3+9x^2+x+3#?

1 Answer
Dec 16, 2016

Answer:

# 3x^3+9x^2+x+3 = (3x^2+1)(x + 3) #

Explanation:

This factors by grouping, as:
# 3x^3+9x^2+x+3 = 3x^2*x + 3x^2*3+x+3 #
# " " = 3x^2(x + 3)+(x+3) #
# " " = (3x^2+1)(x + 3) #

The quadratic term does not factorise further, so this is the fully factorised form.