# How do you factor completely 45x^3+93x^2+30x?

$45 {x}^{3} + 93 {x}^{2} + 30 x$ = $3 x \left(15 {x}^{2} + 31 x + 10\right)$
$3 x \left(15 {x}^{2} + 31 x + 10\right)$ = $3 x \left(5 x + 2\right) \left(3 x + 5\right)$