# How do you factor completely #5a-15a^2#?

##### 1 Answer

Jun 28, 2016

5a(1-3a)

#### Explanation:

There is a common factor of 5a in both terms which can be 'taken out'.

#rArr5a-15a^2=5a(1-3a)# This may be checked by distributing the bracket.

#5a(1-3a)=(5axx1)-(5axx3a)=5a-15a^2#