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How do you factor completely $6x^2-13x+6$ ?

1 Answer

Mar 4, 2018

given,

$6x^2 -13x+6$

$=6x^2 -9x -4x +6$

$=3x(2x-3) -2(3x-3)$

$=(2x-3) (3x-2)$

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