Question

How do you factor completely `bx^2-b = x-b^2x`?

Answer 1

`x=1/b` or `x=-b`

Explanation:

`bx^2-b=x-b^2x`

`=>bx^2+b^2x-x-b=0`

or `bx(x+b)-1(x+b)=0`

or `(bx-1)(x+b)=0`

i.e. either `bx-1=0` i.e. `x=1/b`

or `x+b=0` i.e. `x=-b`