How do you factor completely #x^2 - 8x + 16#?
This is a perfect square trinomial, because the first and last terms are perfect squares
You can also double check by making sure term b (the middle term) satisfies the equation
Factor as a regular trinomial of the form
To factor a trinomial of the form ax^2 + bx + c, a = 1#, you must find two numbers that multiply to c and that add to b.
We must find two numbers that multiply to +16 and add to -8. These two numbers are -4 and -4.
So, (x - 4)(x - 4). Since the parentheses repeats itself twice, we can rewrite the expression as
- Factor the following trinomials using method 1
2 . Factor the following trinomials using method 2
3 . Find the value of