How do you factor fully, if possible #21c^4d^3-28c^2d^5+7cd^3#?

1 Answer
Nov 14, 2016

Answer:

#7cd^3(3c^3 - 4cd^2 + 1)#

Explanation:

You find the lowest form of each constant and variable which is present in each term and factor it out. In this case it would be #7#, #c^1 = c# and #d^3# giving:

#7cd^3(3c^(4-1)d^(3-3) - 4c^(2 - 1)d^(5-3) + 1c^(1-1)d^(3-3))#

#7cd^3(3c^3d^0 - 4cd^2 + 1c^0d^0)#

#7cd^3(3c^3 - 4cd^2 + 1)#