How do you factor $g(1-x) - gx + gx^2$ ?

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Answer 1 · 2018-03-30T01:02:54

We have:

$=g(1 - x - x + x^2)$

$=g(x^2 - 2x+ 1)$

$=g(x- 1)^2$

Hopefully this helps!

Answer 2 · 2018-03-30T01:04:12

$g(x-1)^2$

$g(1-x)-gx+gx^2$

Distribute:
$g-gx-gx+gx^2$

Combine like terms:
$g-2gx+gx^2$

Factor out $g$ with GCF:
$g(1-2x+x^2)$

Factor the quadratic:
$g(x-1)(x-1)$

Express in simplest form:
$g(x-1)^2$

How do you factor g(1-x) - gx + gx^2g(1-x) - gx + gx^2?