How do you factor #k^2 + k - 110#?

1 Answer
Mar 11, 2018

Answer:

#color(blue)((k-10)(k+11)#

Explanation:

Given:

Factorize: #color(red)(k^2 + k - 110#

#y=f(x) = k^2 + k - 110#

Split the middle term to factorize.

#k^2 -10k+11k - 110#

Break the expression into appropriate groups.

Factor #k# and #11# respectively as shown below:

#k(k-10)+11(k-10)#

Next, factor the common term: #(k-10)#

#color(blue)((k-10)(k+11)#

Hope you find this solution useful.