How do you factor r^2-4r+3r2−4r+3?

3 Answers
James
Jun 6, 2018

r^2-4r+3=(r-1)*(r-3)r2−4r+3=(r−1)⋅(r−3)

Explanation:

show below:

r^2-4r+3r2−4r+3

(r-1)*(r-3)(r−1)⋅(r−3)

Jim G.
Jun 6, 2018

(r-1)(r-3)(r−1)(r−3)

Explanation:

"the factors of + 3 which sum to - 4 are - 1 and - 3"the factors of + 3 which sum to - 4 are - 1 and - 3

r^2-4r+3=(r-1)(r-3)r2−4r+3=(r−1)(r−3)

Meave60
Jun 6, 2018

r^2-4r+3=color(blue)((r-1)(r-3)r2−4r+3=(r−1)(r−3)

Explanation:

Factor:

r^2-4r+3r2−4r+3

Find two numbers that when added equal -4−4 and when multiplied equal 33. The numbers -1−1 and -3−3 meet the requirements.

Rewrite the equation as two binomials.

r^2-4r+3=(r-1)(r-3)r2−4r+3=(r−1)(r−3)

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