How do you factor #r^2-4r+3#?

3 Answers
Jun 6, 2018

Answer:

#r^2-4r+3=(r-1)*(r-3)#

Explanation:

show below:

#r^2-4r+3#

#(r-1)*(r-3)#

Jun 6, 2018

Answer:

#(r-1)(r-3)#

Explanation:

#"the factors of + 3 which sum to - 4 are - 1 and - 3"#

#r^2-4r+3=(r-1)(r-3)#

Jun 6, 2018

Answer:

#r^2-4r+3=color(blue)((r-1)(r-3)#

Explanation:

Factor:

#r^2-4r+3#

Find two numbers that when added equal #-4# and when multiplied equal #3#. The numbers #-1# and #-3# meet the requirements.

Rewrite the equation as two binomials.

#r^2-4r+3=(r-1)(r-3)#