How do you factor #t^3 + 6t^2 + 5t#?

Question

1791 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-09-24T16:19:13

#t^3+6t^2+5t=t(t+1)(t+5)#

#t^3+6t^2+5t#

Factor out the GCF #t#.

#t(t^2+6t+5)#

Factor #(t^2+6t+5)#

Find two numbers that when added equal #6#, and when multiplied equal #5#.

The numbers #1# and #5# fit the criteria.

#t(t+1)(t+5)#