# How do you factor t^3 + 6t^2 + 5t?

Sep 24, 2015

${t}^{3} + 6 {t}^{2} + 5 t = t \left(t + 1\right) \left(t + 5\right)$

#### Explanation:

${t}^{3} + 6 {t}^{2} + 5 t$

Factor out the GCF $t$.

$t \left({t}^{2} + 6 t + 5\right)$

Factor $\left({t}^{2} + 6 t + 5\right)$

Find two numbers that when added equal $6$, and when multiplied equal $5$.

The numbers $1$ and $5$ fit the criteria.

$t \left(t + 1\right) \left(t + 5\right)$