# How do you factor the expression 32v^2-2?

Take 2 out as a common factor: $2 \left(16 {v}^{2} - 1\right)$
The factored answer is a "difference of squares": $\left({n}^{2} - {m}^{2}\right) ,$ where n and m are perfect squares.
$2 \left(4 v - 1\right) \left(4 v + 1\right)$