Question

How do you factor the expression `32v^2-2`?

Answer 1

2(4v-1)(4v+1)

Explanation:

Take 2 out as a common factor: `2(16v^2-1)`
The factored answer is a "difference of squares": `(n^2-m^2),` where n and m are perfect squares.
Therefore, when factored as a "difference of squares":
`2(4v-1)(4v+1)`