How do you factor the expression $9x^2 - 16$ ?

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Answer 1 · 2018-03-20T07:12:57

$(3x+4)(3x-4)$

$9x^2-16$

$=> (3x)^2-(4)^2$

The identity for $a^2-b^2$ is equal to

$(a+b)(a-b)$ .

Here , $a=3x$ and $b=4$ .

So , we get $(3x)^2-(4)^2$

$=> (3x+4)(3x-4)$

How do you factor the expression 9x^2 - 169x^2 - 16?