# How do you factor the expression c^3-6c^2-16c?

Feb 1, 2017

$c \left(c - 8\right) \left(c + 2\right)$

#### Explanation:

Each term has a $c$ in it so step one is to factor that out.

$c \left({c}^{2} - 6 c - 16\right)$

Notice that $2 \times \left(- 8\right) = - 16$ and that $2 - 8 = - 6$

So we have:

$c \left(c - 8\right) \left(c + 2\right)$