How do you factor the expression w^3-3w^2-54w w3−3w2−54w?

1 Answer
George C.
Mar 19, 2018

w^3-3w^2-54w = w(w-9)(w+6)w3−3w2−54w=w(w−9)(w+6)

Explanation:

Given:

w^3-3w^2-54ww3−3w2−54w

Note that all of the terms are divisible by ww, so we can separate that out as a factor. Then note that 54 = 9 * 6 54=9⋅6 and 9 - 6 = 39−6=3, so we find:

w^3-3w^2-54w = w(w^2-3w-54) = w(w-9)(w+6)w3−3w2−54w=w(w2−3w−54)=w(w−9)(w+6)

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