# How do you factor the expression w^3-3w^2-54w ?

Mar 19, 2018

${w}^{3} - 3 {w}^{2} - 54 w = w \left(w - 9\right) \left(w + 6\right)$

#### Explanation:

Given:

${w}^{3} - 3 {w}^{2} - 54 w$

Note that all of the terms are divisible by $w$, so we can separate that out as a factor. Then note that $54 = 9 \cdot 6$ and $9 - 6 = 3$, so we find:

${w}^{3} - 3 {w}^{2} - 54 w = w \left({w}^{2} - 3 w - 54\right) = w \left(w - 9\right) \left(w + 6\right)$