How do you factor the expression #x^2 - 10x + 25#?

3 Answers
Apr 22, 2018

Answer:

#x²-10x+25=(x-5)²#

Explanation:

#x²-10x+25#

#Delta=b²-4ac#

#Delta=(-10)²-4*1*25#

#Delta=100-100#

#Delta=0#

So:

#x=-b/(2a)#

#x=10/2=5#

So :

#x²-10x+25=(x-5)²#

\0/ here's our answer !

Answer:

#x²-10x+25=(x-5)²#

Explanation:

#x²-10x+25#

#=x²-5x-5x+25#

#=x(x-5)-5(x-5)#

#=(x-5)(x-5)#

#=(x-5)²#

\0/ here's our answer !

Aug 5, 2018

Answer:

#(x-5)^2#

Explanation:

To factor this, let's do a little thought experiment:

What two numbers sum up to the middle term (#-10#) and have a product of the last term (#25#)?

After some trial and error, we arrive at #-5# and #-5#. This means we can factor this as

#(x-5)(x-5)#, which can be alternatively written as #(x-5)^2#.

Hope this helps!