How do you factor the expression $x^3-3x^2-4x+12$ ?

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Answer 1 · 2016-05-10T21:32:31

$x^3-3x^2-4x+12=(x-2)(x+2)(x-3)$

Factor by grouping:

$x^3-3x^2-4x+12$

$=(x^3-3x^2)-(4x-12)$

$=x^2(x-3)-4(x-3)$

$=(x^2-4)(x-3)$

$=(x-2)(x+2)(x-3)$

How do you factor the expression x^3-3x^2-4x+12x^3-3x^2-4x+12?