How do you factor #x^2-10x-24#?

1 Answer
Mar 5, 2016

Answer:

Factors are #(x-12)(x+2)#

Explanation:

To factorize #ax^2+bx+c=0#, we split #ac# into two factors, whose sum is #b#.

In the polynomial #x^2−10x−24#, the product is #-24# and hence such factors would be #-12# and #2#. Hence splitting middle term this way, we get

#x^2−10x−24=x^2−12x+2x−24# i.e.

#x(x-12)+2(x-12)# or

#(x-12)(x+2)#