# How do you factor x^2-25?

The answer is $\left(x + 5\right) \left(x - 5\right)$ .
$\left({x}^{2} - 25\right)$ fits the pattern of the difference of squares in which $\left({a}^{2} - {b}^{2}\right) = \left(a + b\right) \left(a - b\right)$.
The factorization of $\left({x}^{2} - 25\right) = \left({x}^{2} - {5}^{2}\right)$ =
$\left(x + 5\right) \left(x - 5\right)$