# How do you factor x^2+3x+4x+12?

May 11, 2015

The factors of ${x}^{2} + 7 x + 12$ are $\left(x + 3\right) \left(x + 4\right)$.

Factor ${x}^{2} + 3 x + 4 x + 12$.

Simplify $3 x + 4 x$ to $7 x$.

${x}^{2} + 7 x + 12$

Find two numbers that when added will make 7, and when multiplied will make 12. Numbers 3 and 4 make 7 when added and 12 when multiplied.

$\left(x + 3\right) \left(x + 4\right) = {x}^{2} + 7 x + 12$