How do you factor #x^2-6x-4#?

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Answer 1 · 2018-05-04T00:25:16

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#x^2-6x-4# is in the form of #ax^2+bx+c#

#x=(-b+-sqrt(b^2-4ac))/(2a)#

#x=(6+-sqrt(36+16))/(2)#

#x=(6+-sqrt52)/2#

#x=(6+-sqrt(4*13))/2#

#x=(6+-2sqrt13)/2#

#x=3+-sqrt13#