How do you factor $x^{2} - 6 x - 4$ $x^2-6x-4$ ?

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Answer 1 · 2018-05-04T00:25:16

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$x^{2} - 6 x - 4$ $x^2-6x-4$ is in the form of $a x^{2} + b x + c$ $ax^2+bx+c$

$x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$ $x=(-b+-sqrt(b^2-4ac))/(2a)$

$x = \frac{6 \pm \sqrt{36 + 16}}{2}$ $x=(6+-sqrt(36+16))/(2)$

$x = \frac{6 \pm \sqrt{52}}{2}$ $x=(6+-sqrt52)/2$

$x = \frac{6 \pm \sqrt{4 \cdot 13}}{2}$ $x=(6+-sqrt(4*13))/2$

$x = \frac{6 \pm 2 \sqrt{13}}{2}$ $x=(6+-2sqrt13)/2$

$x = 3 \pm \sqrt{13}$ $x=3+-sqrt13$

How do you factor x^2-6x-4x2−6x−4x^2-6x-4?