How do you factor #-x^2 - x + 6#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Ratnesh Bhosale Feb 28, 2016 #(x+3) & (x-2)# Explanation: #-x^2-x+6# #x^2+x-6# #x^2+3x-2x-6# #x(x+3)-2(x+3)# #(x+3)(x-2)# Factors of above equation are #(x+3) & (x-2)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 935 views around the world You can reuse this answer Creative Commons License