How do you factor $(x - 2y)^2 - 3x(x - 2y)$ ?

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Answer 1 · 2018-04-23T22:46:50

$(x-2y)²-3x(x-2y)=-(3x+2y)(x-2y)$

$(x-2y)²-3x(x-2y)$
$=color(red)((x-2y))(x-2y)color(red)(-3x)(x-2y)$
$=((x-2y)-3x)(x-2y)$
$=(-3x-2y)(x-2y)$
$=-(3x+2y)(x-2y)$
\0/ here's our answer!

How do you factor (x - 2y)^2 - 3x(x - 2y)(x - 2y)^2 - 3x(x - 2y)?