How do you factor #(x - 2y)^2 - 3x(x - 2y)#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Guillaume L. Apr 23, 2018 #(x-2y)²-3x(x-2y)=-(3x+2y)(x-2y)# Explanation: #(x-2y)²-3x(x-2y)# #=color(red)((x-2y))(x-2y)color(red)(-3x)(x-2y)# #=((x-2y)-3x)(x-2y)# #=(-3x-2y)(x-2y)# #=-(3x+2y)(x-2y)# \0/ here's our answer! Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 4152 views around the world You can reuse this answer Creative Commons License