# How do you factor x^3 - 2x^2 + 3x -6 = 0 by grouping?

Aug 6, 2016

=$\left(x - 2\right) \left({x}^{2} + 3\right)$

#### Explanation:

There are 4 terms, but there is no common factor in all of the terms.
Group them into pairs to create a common factor.
There must be a + sign between the pairs. This can be changed later if necessary.

$\left({x}^{3} - 2 {x}^{2}\right) + \left(3 x - 6\right) = 0 \text{ look for common factors}$

=${x}^{2} \left(x - 2\right) + 3 \left(x - 2\right) \text{ there is a common bracket}$

=$\left(x - 2\right) \left({x}^{2} + 3\right)$