How do you factor #x^3+2x^2+4x+8# by grouping?

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Answer 1 · 2017-03-23T01:03:50

See the entire solution process below:

First, rewrite the expression by grouping as:

#(x^3 + 2x^2) + (4x + 8)#

Now factor each of these as:

#((x^2 * x) + (x^2 * 2)) + ((4 * x) + (4 * 2)) ->#

#(x^2(x + 2)) + (4(x + 2))

We can now factor out the #(x + 2)# term leaving:

#(x^2 + 4)(x + 2)#