# How do you factor x^3-8x^2+16x?

Mar 14, 2018

$x {\left(x - 4\right)}^{2}$

#### Explanation:

$x \left({x}^{2} - 8 x + 16\right) =$
$x \left(x - 4\right) \left(x - 4\right) =$
$x {\left(x - 4\right)}^{2}$

It was factored this way because x can be factored out since it is a common factor. $- 4 + \left(- 4\right) = - 8$ and $- 4 \cdot \left(- 4\right) = 16$, so you write $x - 4$ for both. It can be simplified by squaring $x - 4$.