# How do you factor x^3+8x^2-20x?

May 14, 2018

$x \left(x + 10\right) \left(x - 2\right)$
First, you would divide $x$ out of the whole expression to get
$x \left({x}^{2} + 8 x - 20\right)$
You would then factor ${x}^{2} + 8 x - 20$. To factor it, you need to find two numbers that added together equal $8$ and multiplied together equal $- 20$. These two numbers would be $10$ and $- 2$, giving us
$x \left(x + 10\right) \left(x - 2\right)$