How do you factor #x^3 + (x + y)^3#? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer Shwetank Mauria Jan 18, 2017 #x^3+(x+y)^3=(2x+y)(x^2+xy+y^2)# Explanation: Here, we can use the identity #a^3+b^3=(a+b)(a^2-ab+b^2)# Hence #x^3+(x+y)^3# = #(x+(x+y))(x^2-x(x+y)+(x+y)^2)# = #(2x+y)(x^2-x^2-xy+x^2+2xy+y^2)# = #(2x+y)(x^2+xy+y^2)# Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor #x^3 -8#? What are the factors of #x^3y^6 – 64#? How do you know if #x^2 + 10x + 25# is a perfect square? How do you write #16x^2 – 48x + 36# as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor #16x^2-36# using the difference of squares? How do you factor #2x^4y^2-32#? How do you factor #x^2 - 27#? See all questions in Factor Polynomials Using Special Products Impact of this question 1464 views around the world You can reuse this answer Creative Commons License