How do you factor #y^2-16+64#?
This trinomial is a perfect square trinomial, so can be factored as
The square root of 64 is 8 and the square root of
The middle term should be of the form 2ab. In this case, a=y and b= 8
So, 2(y)(8), or 16y, which is the middle term. This short proof justifies that it is indeed a perfect square trinomial.
= (y - 8)(y - 8)
Your answer is
- Out of the following trinomials, which is/are perfect square trinomial(s)?
- Factor the following perfect square trinomial:
Hopefully you understand now!