How do you factor #y= 2x^3 + 16x2 + 7x + 56# ?

1 Answer
Dec 30, 2015

Answer:

Use factor by grouping. The working is shown below.

Explanation:

#y=2x^3+16x^2 + 7x + 56#

#y=(2x^3+16x^2)+(7x+56)# Grouped the terms.

Next step is to factor out the GCF from each group.

#y=2x^2(x+8)+7(x+8)#

Now to factor out GCF of both the groups.

#y=(x+8)(2x^2+7)#

This is the final answer as we can't factor it further.