# How do you factor y= 2x^3 + 16x2 + 7x + 56 ?

Dec 30, 2015

Use factor by grouping. The working is shown below.

#### Explanation:

$y = 2 {x}^{3} + 16 {x}^{2} + 7 x + 56$

$y = \left(2 {x}^{3} + 16 {x}^{2}\right) + \left(7 x + 56\right)$ Grouped the terms.

Next step is to factor out the GCF from each group.

$y = 2 {x}^{2} \left(x + 8\right) + 7 \left(x + 8\right)$

Now to factor out GCF of both the groups.

$y = \left(x + 8\right) \left(2 {x}^{2} + 7\right)$

This is the final answer as we can't factor it further.