# How do you factor #y= 2x^3-2x^2-4x #?

##### 1 Answer

Dec 26, 2015

#### Answer:

#y = 2x^3-2x^2-4x = 2x(x+1)(x-2)#

#### Explanation:

First note that all of the terms are divisible by

#y = 2x^3-2x^2-4x = 2x(x^2-x-2)#

Then notice that if you substitute

#(x^2-x-2) = (x+1)(x-2)#

So we have:

#y = 2x^3-2x^2-4x = 2x(x+1)(x-2)#