How do you factor #y=2x^4+21x^3+49x^2 #?
First identify the factor common to all the terms which is
The bracketed term can then be factored as
Factor f(x) by the systematic new AC Method (Socratic Search)
p' and q' have same sign because ac > 0.
Factor pairs of (ac = 98) --> (2, 49)(7, 14). This sum is 21 = b.
Then, p' = 7 and q' = 14.
Back to f(x) --> 3p = (p')/a = 7/2