# How do you factor y^3 + 3y^2 -4y +12 by grouping?

See explanation below

#### Explanation:

As per given question, the polynomial can't be factorized by grouping. However I assume some possible typo in question.

Assuming

1)

${y}^{3} + 3 {y}^{2} + 4 y + 12$

$= {y}^{2} \left(y + 3\right) + 4 \left(y + 3\right)$

$= \left(y + 3\right) \left({y}^{2} + 4\right)$

2)

${y}^{3} + 3 {y}^{2} - 4 y - 12$

$= {y}^{2} \left(y + 3\right) - 4 \left(y + 3\right)$

$= \left(y + 3\right) \left({y}^{2} - 4\right)$

$= \left(y + 3\right) \left(y + 2\right) \left(y - 2\right)$