How do you factor #y^3 + 3y^2 -4y +12# by grouping?

Question

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Answer 1 · 2018-07-22T19:27:41

See explanation below

As per given question, the polynomial can't be factorized by grouping. However I assume some possible typo in question.

Assuming

1)

#y^3+3y^2+4y+12#

#=y^2(y+3)+4(y+3)#

#=(y+3)(y^2+4)#

2)

#y^3+3y^2-4y-12#

#=y^2(y+3)-4(y+3)#

#=(y+3)(y^2-4)#

#=(y+3)(y+2)(y-2)#