How do you factor #y^3 + 3y^2 -4y +12# by grouping?

1 Answer

Answer:

See explanation below

Explanation:

As per given question, the polynomial can't be factorized by grouping. However I assume some possible typo in question.

Assuming

1)

#y^3+3y^2+4y+12#

#=y^2(y+3)+4(y+3)#

#=(y+3)(y^2+4)#

2)

#y^3+3y^2-4y-12#

#=y^2(y+3)-4(y+3)#

#=(y+3)(y^2-4)#

#=(y+3)(y+2)(y-2)#