# How do you factor y^3 + 7y^2 + y + 7 by grouping?

May 23, 2017

$\left(y + 7\right) \left({y}^{2} + 1\right)$

#### Explanation:

Group the first two terms and the last two terms together:

$\left({y}^{3} + 7 {y}^{2}\right) + \left(y + 7\right)$

Now factor what you can from each group:

${y}^{2} \left(y + 7\right) + 1 \left(y + 7\right)$

Now factor out $y + 7$ from the whole thing:

$\left(y + 7\right) \left({y}^{2} + 1\right)$