# How do you factor #y^3-y^2+y-1 # by grouping?

##### 1 Answer

Jun 9, 2016

#### Explanation:

Given expression is

- On inspection we notice that first two terms have a common factor
#y^2# . - if we take out
#y^2# common out of these two what remains is equal to the last two terms. - The last two do not have any common factor except
#1# .

Let us therefore group first two and last two terms. We rewrite the expression as

Taking out common factor

Taking out the common factor

We have our required factors.