How do you factor #y= 36x^2+132x+121# ?

1 Answer
Jul 23, 2016

Answer:

#y= (6x+11)(6x+11)#

Explanation:

There are many factor combinations, but it is significant that both 36 and 121 are perfect squares. Try those factors first.6

Write down factors and find the cross-product.

#"6 11" rArr 6xx11 = 66#
#"6 11" rArr 6xx11 = 66" "66+66 = 132#

The signs are the same (because of +121)
They are both plus (because of +132)

#y= (6x+11)(6x+11)#