# How do you factor: y=3x^3 - 8x^2 - x + 10?

$y = \left(x - 2\right) \left(3 {x}^{2} - 2 x - 5\right) .$
Since (a - b + c = 0), use shortcut. One factor is (x + 1) and the other is $\left(x - \frac{5}{3}\right)$
$y = \left(x - 2\right) \left(x + 1\right) \left(x - \frac{5}{3}\right)$