How do you factor y=3x^7 - 9x ^6 + 18x ^5 ?

Jul 9, 2016

$3 {x}^{5} \left({x}^{2} - 3 x + 6\right)$

Explanation:

Numerically there is a common factor of 3 (3 , -9 and 18)

With the variable (x^7,x^6" and " x^5) the common factor is ${x}^{5}$

Hence each term has a common factor of $3 {x}^{5}$

Removing the common factor gives

$3 {x}^{5} \left({x}^{2} - 3 x + 6\right)$