How do you factor #y=3x^7 - 9x ^6 + 18x ^5 #?
1 Answer
Jul 9, 2016
Explanation:
Numerically there is a common factor of 3 (3 , -9 and 18)
With the variable (
#x^7,x^6" and " x^5)# the common factor is#x^5# Hence each term has a common factor of
#3x^5# Removing the common factor gives
#3x^5(x^2-3x+6)#
