# How do you factor #y= 4t^5-12t^3+8t^2# ?

##### 1 Answer

Dec 27, 2015

Separate out the common factor

#4t^5-12t^3+8t^2 = 4t^2(t-1)(t-1)(t+2)#

#### Explanation:

First notice that all of the terms are divisible by

#y = 4t^5-12t^3+8t^2#

#=4t^2(t^3-3t+2)#

Next notice that the sum of the coefficients of the terms of

#(t^3-3t+2) = (t-1)(t^2+t-2)#

Notice that the sum of the coefficients of the terms of

#(t^2+t-2) = (t-1)(t+2)#

Putting this all together:

#4t^5-12t^3+8t^2 = 4t^2(t-1)(t-1)(t+2)#