How do you factor #y= 4x^2 + 17x + 4 # ?

1 Answer
Sep 19, 2016

Answer:

#4x^2+17x+4 = (4x+1)(x+4)#

Explanation:

Use an AC method:

Find a pair of factors of #AC = 4*4 = 16# with sum #B = 17#

The pair #16, 1# works, so use this to split the middle term, then factor by grouping:

#4x^2+17x+4 = (4x^2+16x)+(x+4)#

#color(white)(4x^2+17x+4) = 4x(x+4)+1(x+4)#

#color(white)(4x^2+17x+4) = (4x+1)(x+4)#