How do you factor #y= (5x+2)^2 + 11x(5x+2)+30?# ?

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Answer 1 · 2018-03-26T05:08:35

#2(40x^2+21x+17)#

#(5x+2)(5x+2+11x)+30#

#(5x+2)(16x+2)+30#

#80x^2+42x+4+30#

#2(40x^2+21x+17)#

We could try to find the factors of this trinomial using the quadratic formula, however note that the discriminant is negative, namely

#21^2-4*40*17= -2279#

So this is as far as this factors using real numbers.